Thread: Relativity of Simultaneity View Single Post
PF Gold
P: 4,736
 Quote by DaleSpam Now, transforming to the primed coordinates using the above formulas (v=0.5) gives $(t'_A,x'_A)=(0,0)$, $(t'_B,x'_B)=(-.5,1)$, and $(t'_C,x'_C)=(1,-.5)$. So we see that $t_A \ne t_B$ meaning that simultaneity is relative, and the time between A and C is still 1 meaning that time does not dilate.
What happened to gamma?

The way I calculate the three transformed events, I get:

A' = (0,0)
B' = (-0.577,1.1547)
C' = (1.1547,-0.577)

So A and C do not have the same time coordinates so they are not simultaneous.

EDIT: I see that wasn't your point. I should have said, the time between A and C is not the same as before, it's longer in the primed frame. But I wouldn't call that time dilation, it's just different coordinates for a pair of events.