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Feb9-12, 02:38 AM
P: 3,188
Quote Quote by mangaroosh View Post
[..] Thanks for going through the above; the part I don't understand is the initial equations; I read [itex]t'=t-vx[/itex] as meaning [itex]t'[/itex] equals t minus the velocity along the X-axis, but I don't understand why the velocity comes into it.
My interpretation of it would be that, if the clocks which give the time co-ordinates all ran at the same rate, then absolute simultaneity should prevail; and in order for RoS to prevail clocks would have to give different times (co-ordinates). [..]
Just a primer: If you start with a reference clock in your hand, how would (indeed, how could!) you determine what time it is at a distance? That has little or nothing to do with clock rate.