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Feb25-12, 07:57 AM   #6
 
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Quote by DonAntonio View Post
I think it's pretty ridiculous to talk about ramificated (primes), discriminants and stuff to someone asking so basic and beginner's a question as what's the integral closure of Z in Q(sqrt(2))....now common!
While I absolutely agree with you, was it necessary to resurrect this two-year-old thread just to say that?