In this particular case, if we use the Ax=b method, where we then invert A (say with A-1
and premultiply b with this, then we must have that A has an inverse. But A here is not a square matrix, and only square matrices have inverses, so the matrix solutions will not prove fruitful.
On the other hand, for all my spoofery, I am trying to prove that the only solution to α1
=0 and 2α2
=0 is that α1
=0. Can you offer any help?