 Quote by Xyius
Ohh! So it would be..
[tex]P(W)=P(W|W)P(W)+P(W|M)P(M)[/tex]
??
I don't have time to crunch through the numbers at the moment, but I will be sure to check this out later.
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I wouldn't write it that way. Just count out the cases using combinations like you are already doing. How may ways to do each?