Probability: Choosing a girl from a group

Xyius

So choosing 1 woman and 1 man would be
[tex]\frac{\binom{20}{1}\binom{30}{1}}{\binom{50}{2}}[/tex]
And choosing 2 women would be..

[tex]\frac{\binom{20}{2}}{\binom{50}{2}}[/tex]

Plugging this in gives me 0.2405, or answer C! Thanks! :D

EDIT: Assuming that's the correct answer.....

Xyius	So choosing 1 woman and 1 man would be [tex]\frac{\binom{20}{1}\binom{30}{1}}{\binom{50}{2}}[/tex] And choosing 2 women would be.. [tex]\frac{\binom{20}{2}}{\binom{50}{2}}[/tex] Plugging this in gives me 0.2405, or answer C! Thanks! :D EDIT: Assuming that's the correct answer.....