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Xyius
Xyius is offline
#5
Feb27-12, 03:24 PM
P: 435
So choosing 1 woman and 1 man would be
[tex]\frac{\binom{20}{1}\binom{30}{1}}{\binom{50}{2}}[/tex]
And choosing 2 women would be..

[tex]\frac{\binom{20}{2}}{\binom{50}{2}}[/tex]

Plugging this in gives me 0.2405, or answer C! Thanks! :D

EDIT: Assuming that's the correct answer.....