View Single Post
 P: 437 So choosing 1 woman and 1 man would be $$\frac{\binom{20}{1}\binom{30}{1}}{\binom{50}{2}}$$ And choosing 2 women would be.. $$\frac{\binom{20}{2}}{\binom{50}{2}}$$ Plugging this in gives me 0.2405, or answer C! Thanks! :D EDIT: Assuming that's the correct answer.....