So choosing 1 woman and 1 man would be
[tex]\frac{\binom{20}{1}\binom{30}{1}}{\binom{50}{2}}[/tex]
And choosing 2 women would be..
[tex]\frac{\binom{20}{2}}{\binom{50}{2}}[/tex]
Plugging this in gives me 0.2405, or answer C! Thanks! :D
EDIT: Assuming that's the correct answer.....
