Thread: Power series; 2 View Single Post
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 Quote by arl146 yea i meant to change it to n, just slipped my mind after typing. and oops yea, its n*(x-4)^n / n^3 + 1
Try to stay focussed on the problem at hand. For one thing, you're trying to determine the convergence when x = 5 and x = 3. When x = 5, the general term in your series is n/(n3 + 1). Use parentheses!
QUOTE=arl146;3791707]

but ok, soo like .. how do i show the convergence then with 1/n^2[/QUOTE]
 Quote by Mark44 If you are using the comparison test, you need to show that each term of your series is less than the corresponding term of the series you're comparing to. For your problem, $\sum \frac{1}{n^2}$ is a reasonable choice.