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PeterDonis
#6
Mar5-12, 09:24 AM
Physics
Sci Advisor
PF Gold
P: 6,166
Quote Quote by demonelite123 View Post
now i can integrate both sides and i get [itex] t_1 - t_0 = \int_{r_1}^{r_0} \frac{r}{r - 2M}dr = (r_0 - r_1) + 2Mln(r_0 - 2M) - 2Mln(r_1 - 2M) [/itex].

would this be correct? thanks for you replies.
As noted before, to get the final answer you need to multiply the result by 2 because the integral you have given gives the "one-way" time, and you need the "round trip" time. The integral itself looks OK to me.