Why isn't momentum a function of position?
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Mar6-12, 05:50 PM
I don't think the answer is something special to quantum mechanics. Also in the classical Lagrangian/Hamiltonian formalism, conjugate momenta don't depend on their generalized coordinates. So the answer seems to be related to the fact, that a classical state is characterized by
independent values for every degree of freedom.
Time is special, because it is not a conjugate quantity to anything or a function of such quantities. I.e. it's just a parameter and not an observable in Hamiltonian mechanics.
But as I told Tom, for the spin angular momentum operator there is no "intrinsic angle operator" conjugate to it, so why can't the spin angular momeentum operator depend on an angle parameter?