I don't understand how that question is the question that arose in the second part.
Here is what is being said:
"But let’s say you tossed a die out of my view and then said that the results were one of the above. Which series is more likely to be the one you threw? Because the roll has already occurred, the answer is (b). It’s far more likely that the roll produced a mixed bunch of numbers than a series of 1’s."
This does not relate to the first statement. The roll sequence is more likely to produce a string of mixed numbers. However, what we have here is a choice between two specific strings of numbers. Her conclusion, "thus, the answer is (b)" is false. Everything else that she said is technically fine, but largely irrelevant. The probability that the sequence is a mixed sequence of numbers is not the same thing as the probability that the sequence is a PARTICULAR mixed sequence of numbers.