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einfall
#3
Nov16-12, 08:36 AM
P: 11
Thanks for your tentative confirmation.

In what way would it depend on the intended use of that "complement"? Surely it's a geometrically well-defined complex number?

n.b. In every use of this "complement" θ (let's call it θ'), it's called as cos(θ') so the implicit infinity of periodic solutions is irrelevant.