Is Snell's law incompatible with interface conditions? What went wrong?

In summary, the problem is that Snell's law does not seem to hold when applied to the transmitted wave (calculated using the electromagnetic interface conditions). This is likely because the reflected wave is not taken into account.
  • #1
Ngineer
64
1
Hi everyone,

Someone posted this hypothetical problem on a facebook group and I am wondering what your thoughts are.

The issue is that Snell's law does not seem to hold when applied to the transmitted wave (calculated using the electromagnetic interface conditions.) Here is an example:

Suppose we have an interface at y=0 between vacuum (medium 1; n1 = 1) and a material of εr = μr = 10 (medium 2; n2 = 10).

246059

For a plane electromagnetic wave whose electric field is given by the green arrow, we subsequently have:

246061

And a propagation direction along E1xH1:
246062


which corresponds to an angle of 36.87 degrees.

Using the interface conditions, we find that in the second medium, E2 has a unit vector of (x+ 0.132y), and that H2 is in a direction identical to H1 (i.e. z).
This gives rise to a propagation direction of
k2 = -0.132x + y

Which corresponds to an angle of 82.47 degrees.

Now the problematic issue is:
sin(theta2) / sin(theta1) = sin(82.47)/sin(36.87) = 1.65
Whereas
n1/n2 = 1/10 = 0.1.

Doesn't Snell's law stipulate that they're equal? What went wrong?
 

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  • #2
I don't understand how you determined E2 and H2: "Using the interface conditions, we find that in the second medium, E2 has a unit vector of (x+ 0.132y), and that H2 is in a direction identical to H1 (i.e. z). "
 
  • #3
Hi Andy,
E1 = 5V/M * [0.6,0.8] = [3,4,0] V/M
Using the conditions for continuity at the interface:
E2x = E1y = 3
E2y = E1y * (epsilon1/epsilon2) = 4 * 1/10 = 0.4
So E2 = [3, 0.4, 0] V/M
= 3.02 V/M * [ 0.991, 0.1321, 0 ]
For H2,
H1 = [0,0,5/377] A/M Hence H2z = H1z * meu1/meu2 = 0.5/377 A/M

(This got me even wondering, how does the continuity stipulate that H1z = H2z = 5/377 A/M, when due to propagation we require H2z = 3.02/377 A/M!)
 
Last edited:
  • #4
One error: n = √(ε_r μ_r), so if n = 10 and μ_r = 1 (valid for dielectrics), then ε_r = 100.
 
  • #5
Andy Resnick said:
One error: n = √(ε_r μ_r), so if n = 10 and μ_r = 1 (valid for dielectrics), then ε_r = 100.
For the second medium, εr = μr = 10
 
  • #7
ZapperZ said:
The claim of this thread is very odd, considering that one of things that a student in an E&M course often do is to DERIVE Snell's law using Maxwell equations and the boundary conditions, such as this:

https://ocw.mit.edu/courses/materia...-2013/lecture-notes/MIT3_024S13_2012lec22.pdf
Zz.
I'm not making a claim, I'm asking what went wrong in this particular derivation because I can't figure it out.
 
  • #8
Did you consider the reflected wave?
 
  • #9
DrDu said:
Did you consider the reflected wave?
Thanks! that was probably it!
 

1. Is Snell's law always applicable at the interface of two media?

No, Snell's law is not always applicable at the interface of two media. It is only valid for refraction when the two media have different refractive indices and the incident ray is passing from one medium to another.

2. Can Snell's law be used to calculate the refraction of light at a curved interface?

No, Snell's law is only applicable for refraction at a planar interface. When dealing with a curved interface, other factors such as curvature and surface tension must be taken into account.

3. Why does Snell's law fail to explain the refraction of light at the interface of two media with very different refractive indices?

This is because Snell's law assumes that the speed of light is constant in both media. However, in reality, the speed of light changes as it passes through different media with varying refractive indices. Therefore, Snell's law cannot accurately predict the refraction in this scenario.

4. What are some common interface conditions that can affect the accuracy of Snell's law?

Some common interface conditions that can affect the accuracy of Snell's law include the presence of a thin film or layer at the interface, non-uniformities in the media, and extreme angles of incidence.

5. Are there alternative laws or equations that can be used to describe refraction at interfaces?

Yes, there are alternative laws and equations that can be used to describe refraction at interfaces. These include Fermat's principle, which states that light will follow the path that takes the least time, and the Huygens-Fresnel principle, which describes how light waves propagate through different media.

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