Thread: Leibniz Notation View Single Post

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 Quote by danne89 Hey! How's about the second derivate in this notation. Is this right: $$\frac{d(dy/dx)}{dx} = \frac{ \frac{d(dy)}{d(dx)}}{dx} =\frac{d^2y}{d^2y} \frac{1}{dx}= \frac{d^2y}{d^2dx^2}$$
$$\frac{d}{dx}\frac{dy}{dx}=\frac{d^{2}y}{dx^{2}}$$
$$y^{(n)}(x)$$
$$\frac{d^{n}y(x)}{dx^{n}}$$
and it can be seen as appying the operator $\frac{d}{dx}$ "n" times on the function "y(x)".