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Nubcake
#3
Jan10-13, 01:04 PM
P: 35
Quote Quote by jedishrfu View Post
When you change heights you change the barrel's potential energy. By convention we arbitrarily use 0J potential energy at ground level and when you raise it 1.8 m then you get PE = F * d = 200N * 1.8m = 360 J then if you let it fall back to the ground it have 360 J of kinetic energy of movement at ground level which it then dissipates on impact.
I was more concerned about the direction and the force ; doesn't the weight of the barrel act in the opposite direction of movement?