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Jan10-13, 01:04 PM
When you change heights you change the barrel's potential energy. By convention we arbitrarily use 0J potential energy at ground level and when you raise it 1.8 m then you get PE = F * d = 200N * 1.8m = 360 J then if you let it fall back to the ground it have 360 J of kinetic energy of movement at ground level which it then dissipates on impact.
I was more concerned about the direction and the force ; doesn't the weight of the barrel act in the opposite direction of movement?