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Electromagnetic hamiltonian factor of 1/c question
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dextercioby
#
2
Jan23-13, 03:09 PM
Sci Advisor
HW Helper
P: 11,893
You're missing the Hamiltonian for the EM field. It's obvious the 1/c factor comes from the convention to describe the 4 potential, either as A
^{0}
=ϕ/c or just ϕ. If the second option is chosen, you get the 1/c inside the brackets.