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electromagnetic hamiltonian factor of 1/c question
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Jan23-13, 03:09 PM
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dextercioby
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You're missing the Hamiltonian for the EM field. It's obvious the 1/c factor comes from the convention to describe the 4 potential, either as A
0
=ϕ/c or just ϕ. If the second option is chosen, you get the 1/c inside the brackets.