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 Sci Advisor Thanks PF Gold P: 12,203 The (differential) equation of motion for a particle of mass m on a spring with spring constant k and a displacement x from the equilibrium position is m d2x/dt2 = -kx When you solve this, you find a solution of the form x= A sin(ωt - ∅) ∅ is an arbitrary value for the phase of the oscillation. That's where the variable ω comes from. Trig functions involve angles so ω has the dimension of an angle divided by time. Hence it's referred to as an angular frequency. There is one other point and that is that ω is in radians (as all good angles are) so is 2∏f, where f is the frequency in cycles per second (Hz).