Does Producing Sulfuric Acid from Copper Sulfate Pentahydrate Release Oxygen?

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The discussion centers on the historical production of sulfuric acid from copper sulfate pentahydrate, which decomposes into copper dioxide, water, and sulfur trioxide when heated. The key chemical reaction involves sulfur trioxide (SO3) reacting with water (H2O) to form sulfuric acid (H2SO4). A participant questions the potential release of oxygen during this process, noting a perceived absence of an oxygen molecule in the breakdown. The inquiry also explores the possibility of reversing the reaction to recreate green vitriol from copper dioxide and sulfuric acid, prompting a discussion on what components would be necessary to complete this reverse process. The conversation highlights the complexities of chemical reactions and the importance of understanding the reactants and products involved.
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I was recently reading about the method by which sulfuric acid was produced in the old days. Apparently, copper sulfate pentahydrate (green vitriol), when heated up, breaks down into copper dioxide, water, and sulfur trioxide. The sulfur trioxide and water then bond to form sulfuric acid. Now, I'm really weak on chemistry, but by looking at the chemical signatures of these substances it appears that an oxygen molecule is missing. Does this method give off oxygen as a byproduct?

Also, can the process be reversed? Can copper dioxide and sulfuric acid be combined to form green vitriol?
 
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what is missing?

SO_3(g) + H_2O(l) \longrightarrow H_2SO_4(l)

where are we missing oxygen?
 

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