Given height, and velocity thrown upward, find air-time
View Single Post
Jun12-05, 04:08 PM
g=9.8 not -9.8. time of flight is 1.536275359. velocity at the time of impact would be 12+9.8*1.536275359=27,0554985182. Did I do anything wrong?
btw, I assumed that the balloon was thrown downwards. If it were thrown upward, velocity would be the same, flight of time would increase. but if we throw horizontally then, flying time would be 2,5 sec. velocity would be (24,5^2+12^2)^0.5=27,280945731407479928629640660381.
Anything wrong with any of the calculations I made?
Yeah, they're useless to the OP because no one has any idea how you didi t.