Quote by mathwurkz
But doesn't that integral have to be evaluated to get the answer? That's what I can't evaluate. Hence, I went looking to try partial fractions which I can't get either.

So we got:
[tex]i(t)=\frac{1}{L}\int_0^t E(\beta)e^{R/L(t\beta)}d\beta[/tex]
with E(t) being a squarewave.
For now, let's just let L and R both be 1:
What is i(t) in the interval [0,1]? Wouldn't that just be:
[tex]i(t)=\int_0^t e^{(t\beta)}d\beta\quad\text{for}\quad t\in[0,1][/tex]
What about in the interval [1,2]? So that would be:
[tex]i(t)=\int_0^1 E(\beta)e^{(t\beta)}d\beta+\int_1^t E(\beta)e^{(t\beta)}d\beta[/tex]
but the second integral is zero because E(t) is zero in that region so:
[tex]i(t)=\int_0^1 e^{(t\beta)}d\beta\quad\text{for}\quad t\in[1,2][/tex]
Can you figure out what i(t) would be for the next interval?