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Triss
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2
Oct23-05, 07:11 AM
P: 85
perhaps $\vec{x}$? that gives you the standard vector arrow if you like that ;)
[tex] ds^2=d(\overrightarrow{x})^2+dt^2 [/tex]
[tex] ds^2=d(\vec{x})^2+dt^2 [/tex]