Thread: Energy Eigenstates View Single Post
 P: 4,006 Well just apply the Hamiltonian onto the state psi. this state is the sum of three phi-terms. So each phi-state yields : $$H \phi_1 = E_1 \phi_1$$ $$2H \phi_2 = 2E_2 \phi_2$$ $$3H \phi_3 = 3E_3 \phi_3$$ Just add up everything and you get : $$H \Psi =\frac {1}{\sqrt14} (E_1 \phi_1 + 2E_2 \phi_2 + 3E_3 \phi_3)$$ The clue is to write down each energy term as a function of $$E_1$$. You have a formula given to do that. Keep in mind that the coefficients of the psi-wave-function denote the possible energy values for the system Good Luck marlon