Thread: traffic lights
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HallsofIvy
HallsofIvy is offline
#2
Oct28-03, 05:22 AM
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That looks straight forward. If the probability of being stopped is 0.7, then the probability of not being stopped is 0.3. Since these events are independent, the probability of them happening together is their product. Of 6 sets of lights the person is to be stopped at a particular 2 and not at the other 4. That is:
(0.3)4(0.7)2.