|Nov28-06, 08:34 PM||#1|
ice to water to steam
A 55 g ice cube at 0°C is heated until 40 g has become water at 100°C and 15 g has become steam at 100°C. How much energy was added to accomplish the transformation?
I tried using Q=mL for each change and adding them together.
18315+33900= 52215 which is not the correct answer.
|Nov29-06, 12:38 AM||#2|
You have 55g melting (latent heat of fusion) and 55g warming from 0° C to 100° C and then 15g vaporizing (latent heat of vaporization).
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