Hubbles law and Relativity


by .ultimate
Tags: hubbles, relativity
.ultimate
.ultimate is offline
#1
Mar22-07, 01:10 AM
P: 45
According to Hubble's law, Velocity of recession of galaxies is directily proportinal to distance between them

ie v=H0.r

But, according to theory of relativity

Time diliation

t=t0.(underoot 1-v^2/c^2)

as v->c

t=0

That means the universe will expand upto a certain distance ( if the law hold correct) i.e 2.10^10 l.y

After that the galaxies will slow down to the observer

as
Phys.Org News Partner Science news on Phys.org
Review: With Galaxy S5, Samsung proves less can be more
Making graphene in your kitchen
Study casts doubt on climate benefit of biofuels from corn residue
anantchowdhary
anantchowdhary is offline
#2
Mar22-07, 01:32 AM
P: 372
Quote Quote by .ultimate View Post
But, according to theory of relativity

Time diliation

t=t0.(underoot 1-v^2/c^2)

as v->c

t=0
Here i dont think its possible that [tex]v>c[/tex].Also if it were to be so you would get [tex]\gamma [/tex] as a complex number!
.ultimate
.ultimate is offline
#3
Mar22-07, 06:57 AM
P: 45
I meant as v is almost equal to speed of light, will the recession of galaxies slow down? because t~0


Register to reply

Related Discussions
How much is Special Relativity a needed foundation of General Relativity Special & General Relativity 97
Doppler-shift/hubbles-law implies big bang/universe age? Special & General Relativity 11
Hubbles Law violates c? Special & General Relativity 3
Hubbles Law Introductory Physics Homework 5