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conflict between electrodynamics and classical relativity? |
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| Jul3-07, 03:43 AM | #1 |
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conflict between electrodynamics and classical relativity?
Id just like to start by saying I believe relativity is 100% at least in macroscopic terms. However, I'm having trouble seeing what the conflict was between electrodynamics and relativity.
Electrodynamics in a nutshell states that light goes a constant c. relativity states that physical laws are the same in every inertial reference frame. These don't necessarily conflict do they? Yes, if light went c with respect to some global reference frame, they would conflict. However, what if the speed of light was just c with respect to the emitter's reference frame? Wouldn't that fit both theories? It would be like a particle that is always emitted at the same speed relative to the emitter. Is there anything I'm missing that is fundamentally wrong with that? |
| Jul3-07, 05:56 AM | #2 |
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Some thoughts to test your suggestion:
What about if c was the same in all reference frames, as relativity states? Is there a conflict then? If the emitter is going at c and emits a photon in the forward direction, how fast will it be going? |
| Jul3-07, 06:02 AM | #3 |
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Didn't know that there was or ever has been a conflict between Relativity and Electrodynamics. Historically the conflict was between Newtonian Physics and Electrodynamics. The conflict arises in 1867 when Maxwell expressed the relationships between the fundamental electrical laws in form of a wave equation. This was when the speed of electromagnetic waves was found to be a fundamental constant. The idea of a fixed speed of an electromagnetic wave violated the idea of addition of speeds. Einstein, developed Relativity to reconnect Newtonian Mechanics to Electrodynamics. In doing so he showed that Newtonian physics was a approximation to Special Relativity.
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| Jul3-07, 08:20 AM | #4 |
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conflict between electrodynamics and classical relativity? |
| Jul8-07, 05:40 PM | #5 |
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second, does E&M actually predict that c is constant regardless of the emitters speed? If thats true it answers my question, thanks. |
| Jul8-07, 05:44 PM | #6 |
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| Jul9-07, 08:35 PM | #7 |
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JesseM said :
[tex]c = \frac{1}{\sqrt{\mu_0\epsilon_0}}[/tex] but I don't think that the constancy of c regardless of the emitter/receiver relative velocity can be deduced from this. That idea came with SR. If you apply Gallilean relativity to EM, you get discontinous field lines and other nasties. That was one of Einstein's motivations for SR. |
| Jul9-07, 11:20 PM | #8 |
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| Jul10-07, 06:40 AM | #9 |
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| Jul10-07, 06:41 AM | #10 |
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| Jul10-07, 09:19 AM | #11 |
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| Jul10-07, 10:25 AM | #12 |
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| Jul10-07, 03:49 PM | #13 |
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| Jul10-07, 09:00 PM | #14 |
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If you don't believe me, look at this page: |
| Jul11-07, 08:29 AM | #15 |
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Thanks, JesseM. I will study this.
[some time later ...] I've done a simple calculation. Writing the equation of a plane wave travelling in the x-direction with wave number k and phase velocity s = w/k ( w for omega) thus [tex] \phi = Ae^{i(kx-\omega t)}[/tex] Now I make a Gallilean boost x -> x' = x + vt to a frame moving at speed v in the x direction. Substituting x' for x in the wave equation immediately gives the Doppler change in frequency and a phase velocity s' = s - v. Does this mean the speed of the wave is now measured as a different value, despite always being emitted at a constant speed wrt the medium ? |
| Jul12-07, 02:07 PM | #16 |
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Do you understand that in general, when calculating the behavior of moving objects, there is no need to use multiple frames? For example, would you agree that when calculating the results of an elastic collision in classical mechanics, you can use the equations of classical mechanics to find the outcome in a frame where both objects are moving, there's no need to transform into either object's rest frame? |
| Jul12-07, 07:36 PM | #17 |
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OK, at the request of some of the posters, I've split this thread into two parts, since it took off in a different direction. See "relative speed of a photon - mk2" for the split-off part.
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