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there exists one number N |
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| Mar27-08, 02:04 PM | #1 |
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there exists one number N
The set N of natural numbers = {1, 2, 3, 4, ...}.
But there exists one (1) number N, such that N = 12345678910111213... (where the unit's place is at infinity). A good example of an irrational number then would be 1.234567891011121314... |
| Mar27-08, 02:06 PM | #2 |
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| Mar27-08, 04:09 PM | #3 |
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so, put a decimal in front of it.
oh he did that. |
| Mar27-08, 05:13 PM | #4 |
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there exists one number N |
| Mar27-08, 06:05 PM | #5 |
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| Mar27-08, 07:36 PM | #6 |
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| Mar28-08, 06:54 AM | #7 |
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If it were possible to construct any irrational number by putting a decimal into some positive integer, that would imply that the set of irrational numbers is countable.
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| Mar28-08, 01:23 PM | #8 |
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good question |
| Mar28-08, 01:24 PM | #9 |
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| Mar28-08, 01:25 PM | #10 |
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| Mar28-08, 01:27 PM | #11 |
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| Mar28-08, 01:32 PM | #12 |
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1.234567891011... |
| Mar28-08, 01:57 PM | #13 |
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| Mar28-08, 06:01 PM | #14 |
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| Mar30-08, 06:39 AM | #15 |
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| Mar31-08, 04:53 PM | #16 |
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If f(x) = x, then lim (of f(x) as x approaches infinity) = infinity = N. (but the unit's place of N is at infinity.)
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| Mar31-08, 06:12 PM | #17 |
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But since "infinity" is not an integer, you know that N isn't an integer.
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