
#1
Aug1308, 02:44 AM

P: 195

How does y = e^(x(1i)) + e^(x(1+i))
work out to y = (e^x)sinx + (e^x)cosx??? Using Euler's identity I get, y = (e^x)e^ix + (e^x)e^ix y = e^x(cosx  isinx + cosx + isinx) y = e^x(2cosx) 



#2
Aug1308, 03:21 AM

P: 35

why don't you write your equations using [tex] tabs...
it will be more readable by others... 



#3
Aug1308, 03:27 AM

HW Helper
P: 2,618





#4
Aug1308, 08:07 AM

Math
Emeritus
Sci Advisor
Thanks
PF Gold
P: 38,881

Euler's identity 



#5
Aug1308, 08:39 AM

Sci Advisor
HW Helper
Thanks
P: 25,168




Register to reply 
Related Discussions  
Algebraic Manipulation of Euler's Identity Leads to a Strange Result  General Math  3  
[Identity relations] Need help at some odd identity relation problem  Calculus & Beyond Homework  1  
Euler's method  Introductory Physics Homework  4  
Euler's method  Differential Equations  5  
Euler's Relationship! Need Help!  Calculus  8 