
#1
Sep1108, 12:33 PM

P: 120

Is matter going into a black hole the same as antimatter leaving one?
This has confused me for a while... Thanks, Jamie 



#2
Sep1108, 12:56 PM

Mentor
P: 6,037

Matter and antimatter falling into a black hole increase the mass of the black hole. Matter and antimatter "leaving" (Hawking radiation) a black hole decrease the mass of the black hole. 



#3
Sep1108, 01:02 PM

P: 120

But wouldn't the antimatter and matter anihilate one another inside the black hole?




#4
Sep1108, 01:08 PM

Mentor
P: 6,037

Black hole matter/antimatter
My point was that since matter falling into a black hole increases the black hole's mass and antimatter leaving a black hole decreases a black hole's mass, these two processes are not the same




#5
Sep1108, 01:11 PM

P: 120

Is that due to the conservation of energy and mass?




#8
Sep1108, 01:55 PM

Mentor
P: 6,037

For example, an electron has negative electric charge, and a positron (anitmatter electron) has positive electric charge. If a particle and corresponding antiparticle collide, they annihilate each other, releasing energy. 



#9
Sep1108, 04:49 PM

PF Gold
P: 3,021

Assuming the electron and positron are the same thing(? same mass, etc) differing only in charge: 1. Why don't an electron and positron settle into quantum mechanical orbitals about each other similar to the traditional electron and nucleus? 2. If an high energy electron can in fact be made to collide with a (proton based) nucleus, why does it not 'annihilate' some 1/1800 th of the much larger proton? 


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