Equation Evaluation Problem in Mathematica

S_David

Hello,

I have the following line in Mathematica:

Code:

Print[Pout = (2^-Q*E^(A/2))/SNR \!\(
\*UnderoverscriptBox[\(\[Sum]\), \(q = 0\), \(Q\)]Binomial[Q, q] \(
\*UnderoverscriptBox[\(\[Sum]\), \(n = 0\), \(Ne + q\)]
FractionBox[
SuperscriptBox[\((\(-1\))\), \(n\)], \(a[n]\)] Re[
\*FractionBox[\(Meq[\(-
\*FractionBox[\(A + \((2*Pi*I*n)\)\), \(2*SNR\)]\)]\), 
FractionBox[\(A + \((2*Pi*I*n)\)\), \(2*SNR\)]]]\)\)]

But the problem is that for different values of SNR, the result will be the same all the time. Why is that happening? A, Q, and Ne are all constants.

Thanks in advance

Hepth

What are some examples of what A Q and Ne are so i can try it?
and what is meq?

S_David

Quote by Hepth

What are some examples of what A Q and Ne are so i can try it?
and what is meq?

Try these expressions:

Code:

A=23
Q=15
Ne=21
Meq[s_]:=1/(1-s)

Regards

Hepth

and also, the a[n] function or array?

but before that make sure youre clearing any variables youre reusing.
restarting the kernel does that.

S_David

Quote by Hepth

and also, the a[n] function or array?

but before that make sure youre clearing any variables youre reusing.
restarting the kernel does that.

Assume

Code:

a[n]=1

How clear all variables? I have many of them.

Regards

S_David

I have the same problem again in the following code:

Code:

gA = 10;
M = 1;
Ne = 1;
If[M >= 1, m = M, m = 0];
For[SNRdB = 0, SNRdB <= 10, SNRdB++,
 SNR = 10^(SNRdB/10);
 Print[F1 = \!\(
\*UnderoverscriptBox[\(\[Sum]\), \(r = m\), \(M\)]\(
\*UnderoverscriptBox[\(\[Sum]\), \(i = 0\), \(M - r\)]\(
\*UnderoverscriptBox[\(\[Sum]\), \(j = 0\), \(r + i\)]\(
\*UnderoverscriptBox[\(\[Sum]\), \(k = 0\), \(j*\((Ne - 1)\)\)]
\*SuperscriptBox[\((\(-1\))\), \(i + j\)]*Binomial[M, r]*
        Binomial[M - r, i]*Binomial[r + i, j]*
\*SuperscriptBox[\(E\), 
FractionBox[\(\(-j\)*SNR\), \(gA\)]]*
\*SuperscriptBox[\((
\*FractionBox[\(SNR\), \(g\)])\), \(k\)]\)\)\)\)]]
For[SNRdB = 0, SNRdB <= 10, SNRdB++,
 SNR = 10^(SNRdB/10);
 Print[F2 = 1 - \!\(
\*UnderoverscriptBox[\(\[Sum]\), \(r1 = m\), \(M - 1\)]\(
\*UnderoverscriptBox[\(\[Sum]\), \(i1 = 1\), \(M - r1\)]\(
\*UnderoverscriptBox[\(\[Sum]\), \(j1 = 1\), \(r1 + i1\)]\(
\*UnderoverscriptBox[\(\[Sum]\), \(k1 = 0\), \(j1*\((Ne - 1)\)\)]
\*SuperscriptBox[\((\(-1\))\), \(i1 + j1\)]*Binomial[M, r1]*
         Binomial[M - r1, i1]*Binomial[r1 + i1, j1]*
\*SuperscriptBox[\(E\), 
FractionBox[\(\(-j1\)*SNR\), \(gA\)]]*
\*SuperscriptBox[\((
\*FractionBox[\(SNR\), \(g\)])\), \(k1\)]\)\)\)\)]]

1-1/\[ExponentialE]^(1/10)

1-\[ExponentialE]^-1/10^(9/10)

1-\[ExponentialE]^-1/10^(4/5)

1-\[ExponentialE]^-1/10^(7/10)

1-\[ExponentialE]^-1/10^(3/5)

1-\[ExponentialE]^-1/Sqrt[10]

1-\[ExponentialE]^-1/10^(2/5)

1-\[ExponentialE]^-1/10^(3/10)

1-\[ExponentialE]^-1/10^(1/5)

1-\[ExponentialE]^-1/10^(1/10)

1-1/\[ExponentialE]

1

1

1

1

1

1

1

1

1

1

1

Why is the second part constant, even though it is a dependent on SNR?

Regards

Hepth

Because of your sums and their indices. To fix this, add:

If[M > 1, m = M, m = 0];

before the second For loop. It changes the greater than equal to to just a greater than. That way the second sum in the second for loop doesn't go from 1 to 0 (1 to M-r1 == M-m==0)

Hepth

As for your first question, I DO get something different each time I change SNR.

S_David

Quote by Hepth

As for your first question, I DO get something different each time I change SNR.

Really? How is that? Try to put the SNR in a For[] loop, and tell me what will happen. Because I am using a For[] loop actually.

Regarding your previous post, I have doubts that I have something wrong in the mathematical equations. So, I will double check them and see what happen then.

Thank you

Hepth

FOR:

Code:

A = 23;
Q = 15;
Ne = 21;
Meq[s_] := 1/(1 - s)
a[n_] = 1;
For[SNRdB = 0, SNRdB <= 10, SNRdB++,
  SNR = 10^(SNRdB/10);
Print[
   Pout =
          Refine[(1.0) (2^-Q*E^(A/2))/SNR

[tex]
\left.\left.\left.\sum _{q=0}^Q \text{Binomial}[Q,q]\sum _{n=0}^{\text{Ne}+q} \frac{(-1)^n}{a[n]}\text{Re}\left[\frac{\text{Meq}\left[-\frac{A+(2*\text{Pi}*I*n)}{2*\text{SNR}}\right]}{\frac{A+(2*\text{Pi}*I*n)}{2*\text{SNR}}}\right]\right]\right]\right]
[/tex]

The changes I made were adding the Refine to simplify the complex stuff, and multiplying by 1.0 to give me a real value.
I also added the SNR changing in the for loop. Looks like it changes when SNR does. Or did I do something wrong?

EDIT: oops, heres my output:
343.991

424.207

520.658

635.431

770.336

926.63

1104.7

1303.75

1521.56

1754.43

1997.27

Hepth

Quote by S_David

Regarding your previous post, I have doubts that I have something wrong in the mathematical equations. So, I will double check them and see what happen then.

Thank you

What I mean is that for your given values, you have a sum over
[tex]
\sum _{\text{r1}=m}^{M-1} \sum _{\text{i1}=1}^{M-\text{r1}} \sum _{\text{j1}=1}^{\text{r1}+\text{i1}} \sum _{\text{k1}=0}^{\text{j1}*(\text{Ne}-1)}
[/tex]
but you have defined :
If[M >= 1, m = M, m = 0];
and M IS 1, so m=M=1;
Then in your sum
[tex]
\sum _{\text{r1}=m}^{M-1} \sum _{\text{i1}=1}^{M-\text{r1}}
[/tex]
you have:
r1 from {m to M-1} which is r1 from {1 to (1-1)} or {1 to 0}
then you have i1 from {1 to M-r1} which is {1 to (1-1)} or {1 to 0}

So it doesnt sum anything.
see :
[tex]
M=1;m=1;\sum _{\text{r1}=m}^{M-1} \sum _{\text{i1}=1}^{M-\text{r1}} 1==0
[/tex]

S_David

Yes, now the fake code is working. I said fake because I gave you fake parameters, so the values you got are not the expected one, because there are not in the range between 0 and 1 as it must be by definition. When I did a slight change toward the real parameters I got the expected results as following:

Code:

A = 23;
Q = 15;
Ne = 21;
Meq[s_] := 1/(1 - 0.5 s)^4 ;
a[n_] = If[n == 0, 2, 1];
For[SNRdB = 0, SNRdB <= 10, SNRdB++,
 SNR = 10^(SNRdB/10);
 Print[Pout = Refine[(1.0) (2^-Q*E^(A/2))/SNR \!\(
\*UnderoverscriptBox[\(\[Sum]\), \(q = 0\), \(Q\)]Binomial[Q, q] \(
\*UnderoverscriptBox[\(\[Sum]\), \(n = 0\), \(Ne + q\)]
FractionBox[
SuperscriptBox[\((\(-1\))\), \(n\)], \(a[n]\)] Re[
\*FractionBox[\(Meq[\(-
\*FractionBox[\(A + \((2*Pi*I*n)\)\), \(2*SNR\)]\)]\), 
FractionBox[\(A + \((2*Pi*I*n)\)\), \(2*SNR\)]]]\)\)]]]

0.142877

0.246246

0.390748

0.564677

0.738295

0.875494

0.956523

0.989842

0.998584

0.999898

0.999997

But when I turn my attention to my real, relatively long code, I faced with the same problem again, although I used the same procedure as you described. I don't know why.

Best Regards

Similar Threads for: Equation Evaluation Problem in Mathematica
Thread	Forum	Replies
Write this Equation using Mathematica	Math & Science Software	9
Maple 12 problem: long evaluation	General Math	0
Evaluation of Strike and the 3 point problem....	Biology, Chemistry & Other Homework	1
Differential Equation and Mathematica	Math & Science Software	4
Mathematica Evaluation Time	Math & Science Software	4

Hepth Recognitions: Gold Member	What are some examples of what A Q and Ne are so i can try it? and what is meq?

Hepth Recognitions: Gold Member	Equation Evaluation Problem in Mathematica and also, the a[n] function or array? but before that make sure youre clearing any variables youre reusing. restarting the kernel does that.