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image operator is normal iff ||Tv||=||T*v||, simple proof help Share It Thread Tools Search this Thread image
Old Nov22-09, 08:12 PM       Last edited by boboYO; Nov22-09 at 08:26 PM..            #1
boboYO

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operator is normal iff ||Tv||=||T*v||, simple proof help




I am having trouble understanding 7.6 . Specifically, getting from the 2nd line to the first line. How do we know that T*T-TT* is self adjoint?
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Old Nov22-09, 10:17 PM                  #2
HallsofIvy

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Re: operator is normal iff ||Tv||=||T*v||, simple proof help

(AB)*= B*A* and (A*)*= A.

The adjoint of T*T-TT* is (T*T- TT*)*= (T*T)*- (TT*)*= (T*)(T**)- (T**)T*. And the adjoint is 'dual'- that is, T**= T so that becomes T*T- TT* again.
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Old Nov23-09, 12:49 AM                  #3
boboYO

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Re: operator is normal iff ||Tv||=||T*v||, simple proof help

Originally Posted by HallsofIvy View Post
(AB)*= B*A* and (A*)*= A.

The adjoint of T*T-TT* is (T*T- TT*)*=(T*T)*- (TT*)*= (T*)(T**)- (T**)T*. And the adjoint is 'dual'- that is, T**= T so that becomes T*T- TT* again.
Ahh thank you very much, I got confused and thought (AB)*=A*B*.
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