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Electrostatic force question with coulombs law

by bofford4
Tags: coulumbs, electrostatic, law, magnitude
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bofford4
#1
Jan11-10, 11:30 PM
P: 3
1. The problem statement, all variables and given/known data

A particle of charge of +4.20 x 10^-6 C is 12.0 cm distant from a second particle of charge of -1.70 x 10^-6 C. Calculate the magnitude of the electrostatic force between the particles.

2. Relevant equations

Coulombs law is F = (K*Q1*Q2) / R^2 where k = 8.99*10^9, q1 and q2 are the charges, and R is the distance in meters

3. The attempt at a solution

Im hoping im just making a simple mistake and not seeing it for this question cause this really seems like plug and chug.

K Q1 Q2 R
so I did (8.99 x 10^9)(4.20x10^-6)(-1.70x10^-6) / (.12)^2

= -4.457 N

that gave me a wrong answer so i tried different variations of putting the decimal like -4457.541, 44.57 and -44.57. What am i doing wrong, i might have just fudged up since I'm doing this by hand but I'm not seeing it. Either that or I have done something fundamentally wrong and don't know any better. It's been a while since I've done a class like this so any help is appreciated.
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ehild
#2
Jan11-10, 11:53 PM
HW Helper
Thanks
P: 10,344
The problem asks the magnitude of the force, which is positive. The number itself is good.

ehild
bofford4
#3
Jan12-10, 01:58 AM
P: 3
heh well like i said it's been awhile, I kept thinking since they attracted the force would be negative. Thanks a lot though, guess i just needed a second pair of eyes


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