
#1
Mar410, 10:23 AM

P: 2

Many thanks in advance
Suppose x is normal variable x~N(a,b) and y=160*x^2 I need calculate E(y)=∫yf(y)d(y) f(y) is the density function of y how can I write it as an integral of x since we know x's distribution, I mean use the density function of x to substitute the original integral Can I just use E(y)=E(160 x^2)= ∫ 160 x^2 f(x) d(x) then I can use f(x), which is the density function of normal. Seems right, but seems wrong, seems I use f(x) to substitute x directly! 



#2
Mar410, 09:12 PM

P: 4

You can do it the way you suggested (it is logically correct), but I believe it will make more work for yourself (but I didn't look at it because there is a cleaner way).
Here are a few hints that should help: Remember that the expected value function is a linear operator so [tex] E(Y)=E(160X^2)=160E(X^2) [/tex] and [tex] V(X)=E(X^2)[E(X)]^2 [/tex] 


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