Register to reply

Athlete jumps at angle with distance find speed

by afa
Tags: angle, athlete, distance, jumps, speed
Share this thread:
afa
#1
Sep26-10, 11:26 AM
P: 8
1. The problem statement, all variables and given/known data

Leaves the ground at a 33.6 degree angle and travels at 7.77 m. What is take off speed?
If speed were increased by 4% how much longer would the jump be?

2. Relevant equations

Vx=Vcos(theta)

3. The attempt at a solution

7.77=vcos33.6 got 9.33 but says it wrong, then I added 4% to this and did 9.7cos33.6 which also seems to be wrong..what am I missing?
Phys.Org News Partner Science news on Phys.org
Experts defend operational earthquake forecasting, counter critiques
EU urged to convert TV frequencies to mobile broadband
Sierra Nevada freshwater runoff could drop 26 percent by 2100
Juggernaut
#2
Sep26-10, 12:20 PM
P: 4
Time my friend-time. What`s the time what it takes to travel.
JaredJames
#3
Sep26-10, 12:20 PM
P: 3,387
Hi afa, could you be a little more specific please, you say he travels 7.77m, but where? Horizontally / Vertically / Diagonally? Is this all of the question or is there more detail to it?

Jared

dmkeddy
#4
Oct16-10, 11:40 AM
P: 5
Athlete jumps at angle with distance find speed

I'm having a similar problem:
An athlete executing a long jump leaves the ground at an angle of 30 degrees and travels 8.90m. What was the take-off speed?
JaredJames
#5
Oct16-10, 11:45 AM
P: 3,387
Both responses from juggernaut and myself above apply to this second problem as well.

Jared
dmkeddy
#6
Oct16-10, 11:58 AM
P: 5
travels horizontally 8.90m, no vertical displacement, time is unknown, how do I solve for two variables? Or what do I substitute velocity or time with to solve for the other?
JaredJames
#7
Oct16-10, 12:00 PM
P: 3,387
Leaves the ground at 30 degrees, but there's no vertical displacement?
JaredJames
#8
Oct16-10, 12:03 PM
P: 3,387
You really do need the time factor, and based on what you have given you can't calculate it as far as I can tell.

I'm not sure if you can solve with only two variables. Try rearranging your equations of motion to get something you can solve (perhaps simultaneously).

You can't just substitute time or velocity as they'll generate different answers.

dmkeddy, you should start your own threads for things like this and not hijack an old one as it will gain you a better response.
lvslugger36
#9
Oct16-10, 12:38 PM
P: 16
Since you have to assume that his y displacement is zero by the time he lands, you could use the range equation for this which is (v^2)sin(2x)/g. You know the range is 7.77 and you know x, which is the angle. So solve for v. For the second case, all is being kept constant, except for velocity. So the equation should be kept normal but except for where you write v^2 write (1.04v)^2. If you simplify, you'll note that everything is the same except for the 1.04^2. Hence, just multiply 7.77 by 1.04^2.


Register to reply

Related Discussions
How to find Vf when you have muK, distance and an angle? (answer as soon as possible) Introductory Physics Homework 2
Find distance before rest given length and angle of incline Introductory Physics Homework 11
Zero angle launch problem: Find height given inital speed and angle Introductory Physics Homework 1
Given angle and distance traveled find initial velocity Introductory Physics Homework 3