|Nov17-10, 11:34 PM||#35|
So if I rotate on the Mohr's circle by 90 degrees I will reach the max and min shear stresses?
|Nov18-10, 04:25 PM||#36|
I think it would help you immensely to go back and read up on Mohr's circle to understand what it represents.
|Nov23-10, 04:49 AM||#37|
Your Mohr's circle is almost complete. Try not to forget to draw the sigma-tau reference before you draw a circle. Then you will see that the circle is on the left side of the reference (Uniaxial compression). Note that the right part of the circle touches the origin. I think now the problem solved. If you want stresses at X’Y’, just rotates the horizontal line through the angle you want (it doesn’t matter whether the angle is given since, generally, we often need the principle stresses and maximum shear stress which are on the horizontal and vertical lines)
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