## changing factor of centripetal acceleration

1. The problem statement, all variables and given/known data
A particle moves in a circular path of radius r with speed v. It then increases its speed to 19v while traveling along the same circular path. By what factor has the centripetal acceleration of the particle changed?

2. Relevant equations
ac=v^2/r

3. The attempt at a solution
Tried solving for v in terms of a and r to no avail.
1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

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 Mentor Blog Entries: 1 What's the centripetal acceleration when the speed is v? When the speed is 19v? Compare.
 Recognitions: Gold Member Homework Help Science Advisor If the initial centripetal acceleration is v^2/r, then try substituting 'v' with '19v', to get the new centripetal acceleration, then compare the 2 values.

## changing factor of centripetal acceleration

 Quote by dandy9 Tried solving for v in terms of a and r to no avail.
This question is so ridiculously simple that it creates a thinking-trap! It is tempting to think "It can't be that easy... must do some difficult equation solving .... etc."
It is good to know that things are not always complicated. Sometimes the answer is right in front of you