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triple integral-spherical coordinates |
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| Apr10-11, 02:50 PM | #1 |
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triple integral-spherical coordinates
1. The problem statement, all variables and given/known data
Here is exactly what the problem says: Let T be a solid of density one that lies below x^2+y^2+z^2=9 and above the XY-plane. a) Use the triple integral to find its mass. b) Find the centroid. 2. Relevant equations I believe that this should be an integral in spherical coordinates. I know the relevant equation is p^2sin(phi) dpd(phi)d(theta). 3. The attempt at a solution Obviously the first step is to set up the triple integral in spherical coordinates. I set x^2+y^2+z^2=9 and changed it to p^2=9. This left me with the limits of integration for p being from 0 to 3. I know that theta's integral is normally from 0 to 2(pie). I have no clue how to solve for the 'phi' limits and obviously I can't complete the problem until I do. Please advise as soon as possible what I should do. Thanks! 1. The problem statement, all variables and given/known data 2. Relevant equations 3. The attempt at a solution |
| Apr10-11, 03:48 PM | #2 |
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hi mcc123pa! welcome to pf!
![]() (have a theta: θ and a phi: φ and a pi: π and try using the X2 icon just above the Reply box )φ is the latitude (or co-latitude), and it goes from the pole to the equator, so that's … ?
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| Apr10-11, 03:54 PM | #3 |
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This is not the usual definition of φ in spherical coordinates. Usually φ is the polar coordinate (analogous to longitude, but just starting at 0 and ending at 360, instead of being split between west and east), and θ is the co-latitude (90 degrees-latitude, with latitudes being negative below the x-y plane).
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| Apr10-11, 04:03 PM | #4 |
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triple integral-spherical coordinates
Hi Matterwave!
![]() No, it's ok … engineers do it the other way round! |
| Apr10-11, 10:59 PM | #5 |
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Hi everyone- thanks for the help so far....
tiny-tim, From the pole to the equator, that's pie/2. Is that correct? So I guess in the case that is correct, the limits are as follows: p = from 0 to 3 phi = from 0 to (pie)/2 theta = from 0 to (2pie) Please confirm if I have this right everyone. Thanks for your help! |
| Apr10-11, 11:59 PM | #6 |
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| Apr11-11, 12:19 AM | #7 |
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Thanks LCKurtz!! I'll remember it's pi not pie from now on...thanks for the tip!!
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