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triple integral-spherical coordinates

 
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Apr10-11, 02:50 PM   #1
 

triple integral-spherical coordinates


1. The problem statement, all variables and given/known data

Here is exactly what the problem says:
Let T be a solid of density one that lies below x^2+y^2+z^2=9 and above the XY-plane.
a) Use the triple integral to find its mass.
b) Find the centroid.

2. Relevant equations

I believe that this should be an integral in spherical coordinates. I know the relevant equation is p^2sin(phi) dpd(phi)d(theta).

3. The attempt at a solution

Obviously the first step is to set up the triple integral in spherical coordinates. I set x^2+y^2+z^2=9 and changed it to p^2=9. This left me with the limits of integration for p being from 0 to 3. I know that theta's integral is normally from 0 to 2(pie). I have no clue how to solve for the 'phi' limits and obviously I can't complete the problem until I do. Please advise as soon as possible what I should do. Thanks!
1. The problem statement, all variables and given/known data



2. Relevant equations



3. The attempt at a solution
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Apr10-11, 03:48 PM   #2
 
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hi mcc123pa! welcome to pf!

(have a theta: θ and a phi: φ and a pi: π and try using the X2 icon just above the Reply box )

φ is the latitude (or co-latitude), and it goes from the pole to the equator, so that's … ?
Apr10-11, 03:54 PM   #3
 
This is not the usual definition of φ in spherical coordinates. Usually φ is the polar coordinate (analogous to longitude, but just starting at 0 and ending at 360, instead of being split between west and east), and θ is the co-latitude (90 degrees-latitude, with latitudes being negative below the x-y plane).
Apr10-11, 04:03 PM   #4
 
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triple integral-spherical coordinates


Hi Matterwave!

No, it's ok …
engineers do it the other way round!
Apr10-11, 10:59 PM   #5
 
Hi everyone- thanks for the help so far....

tiny-tim,

From the pole to the equator, that's pie/2. Is that correct?

So I guess in the case that is correct, the limits are as follows:

p = from 0 to 3

phi = from 0 to (pie)/2

theta = from 0 to (2pie)

Please confirm if I have this right everyone. Thanks for your help!
Apr10-11, 11:59 PM   #6
 
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Quote by mcc123pa View Post
Hi everyone- thanks for the help so far....

tiny-tim,

From the pole to the equator, that's pie/2. Is that correct?

So I guess in the case that is correct, the limits are as follows:

p = from 0 to 3

phi = from 0 to (pie)/2

theta = from 0 to (2pie)

Please confirm if I have this right everyone. Thanks for your help!
That's right. But it is "pi", not "pie".
Apr11-11, 12:19 AM   #7
 
Thanks LCKurtz!! I'll remember it's pi not pie from now on...thanks for the tip!!
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