Verify this Trig Identity

larymac47

1-(sin^6x+cos^6x)=(3sin^2x)(cos^2x)

I got this far:

1-(sin^2x+cos^2x)(sin^4x-sin^2xcos^2x+cos^4x)=(3sin^2x)(cos^2x)
1-(sin^4x-sin^2xcos^2x+cos^4x)=(3sin^2x)(cos^2x)

jhae2.718

I'd start by manipulating one of the sides.

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larymac47	Verify this Trig Identity Tweet 1-(sin^6x+cos^6x)=(3sin^2x)(cos^2x) I got this far: 1-(sin^2x+cos^2x)(sin^4x-sin^2xcos^2x+cos^4x)=(3sin^2x)(cos^2x) 1-(sin^4x-sin^2xcos^2x+cos^4x)=(3sin^2x)(cos^2x)

jhae2.718 Blog Entries: 9 Recognitions: Gold Member	I'd start by manipulating one of the sides.