|May11-11, 03:23 AM||#1|
Why is the cube of a unitary operator = identity matrix?
If A is unitary I understand that it obeys AA+=1 because A-1=A+.
Why does A3=1?
The explanation simply says that "A just permutes the basis vectors"..
It then goes on to say that since A3=1, then eigenvalue a3=1 also, which are 1, ei.2pi.theta/3, and ei.4pi.theta/3. This would make sense to me if I knew why A3=1..
Many thanks in advance!
|May11-11, 03:29 AM||#2|
What is this operator A we are talking about? Just any random Unitary operator? It doesn't seem to be true for any unitary operator...
|May11-11, 03:30 AM||#3|
You must have a specific operator in mind because that's not true in general.
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