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When p(A)=0 iff p(B)=0 for any polynomial,why same minimal polynomial? |
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| Jun13-11, 02:00 AM | #1 |
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When p(A)=0 iff p(B)=0 for any polynomial,why same minimal polynomial?
For two matrices A and B, when p(A)=0 iff p(B)=0 for any polynomial, what will happen? i read that A and B have the same minimal polynomial, why?
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| Jun13-11, 07:57 AM | #2 |
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and [tex]m_B (B) = 0\Rightarrow m_B (B) = 0 \Rightarrow m_A / m_B ^{(2)}[/tex] [tex]\overset {(1), (2)}{\Rightarrow} m_A = k \cdot m_B[/tex] with k a constant. But [tex]m_A, m_B[/tex] are both monic polynomials so, [tex]k=1[/tex] and finally [tex]m_A = m_B.[/tex] |
| Jun13-11, 02:13 PM | #3 |
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Pretty much the same thing but in slightly differentwords:
Suppose PA(x), of degree n, is the minimal polynomial for A. Then PA(A)= 0 so PA(B)= 0. If This is not the minimal polynomial for B, there exist a polynomial PB, of degree m< n, such that PB(A)= 0. But then PB(A)= 0 contradicting the fact that the mininal polynomial of A has degree n> m. |
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