## product of compact sets compact in box topology?

So Tychonoff theorem states products of compact sets are compact in the product topology.

is this true for the box topology? counterexample?

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 if S_n is the set with empty sets in each index except n where for index n you have [0,1], then {S_n} is an open cover with no finite subcover...i think

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## product of compact sets compact in box topology?

 Quote by spicychicken if S_n is the set with empty sets in each index except n where for index n you have [0,1], then {S_n} is an open cover with no finite subcover...i think
Such a sets will always be empty. Try to consider a cover by all sets of the form

$$\prod_{n\in \mathbb{N}}{A_i}$$

Where Ai=[0,0.6[ or Ai=]0.5,1]