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product of compact sets compact in box topology? |
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| Jul20-11, 11:33 AM | #1 |
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product of compact sets compact in box topology?
So Tychonoff theorem states products of compact sets are compact in the product topology.
is this true for the box topology? counterexample? |
| Jul21-11, 08:08 AM | #2 |
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A counterexample is [itex]\prod_{n\in \mathbb{N}}{[0,1]}[/itex]. Can you show why?
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| Jul21-11, 01:17 PM | #3 |
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if S_n is the set with empty sets in each index except n where for index n you have [0,1], then {S_n} is an open cover with no finite subcover...i think
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| Jul21-11, 02:24 PM | #4 |
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product of compact sets compact in box topology?[tex]\prod_{n\in \mathbb{N}}{A_i}[/tex] Where Ai=[0,0.6[ or Ai=]0.5,1] |
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