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[Dot Product] Vector Proection |
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| Nov3-11, 12:05 PM | #1 |
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[Dot Product] Vector Proection
1. The problem statement, all variables and given/known data
![]() 2. Relevant equations ![]() ![]() 3. The attempt at a solution I am not sure what to do here -- I know that the projection of u onto a "dotted" with w = 0 by definition, but I don't know how to show this. ![]() ![]() added this second part after plugging in for the definition of the projection we derived in class, then simplified. . . |
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| Nov3-11, 03:43 PM | #2 |
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anyone?
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| Nov3-11, 04:25 PM | #3 |
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Recognitions:
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Hi Highway!
![]() You have an expression for the projection. Can you substitute that (and only that) in the formula you have for w? To show that 2 vectors are orthogonal, you need to show that their dot product is zero. That is, that [itex]\vec a \cdot \vec w = 0[/itex]. What you need to know, is that there are calculation rules for dot products. For instance [itex]\vec a \cdot (\vec b+\vec c) = \vec a \cdot \vec b + \vec a \cdot \vec c[/itex]. Can you simplify the expression for [itex]\vec a \cdot \vec w = 0[/itex]? |
| Nov3-11, 04:45 PM | #4 |
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[Dot Product] Vector Proection
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| Nov3-11, 04:58 PM | #5 |
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Recognitions:
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Congrats!
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