
#1
Nov311, 12:05 PM

P: 349

1. The problem statement, all variables and given/known data
2. Relevant equations 3. The attempt at a solution I am not sure what to do here  I know that the projection of u onto a "dotted" with w = 0 by definition, but I don't know how to show this. added this second part after plugging in for the definition of the projection we derived in class, then simplified. . . 



#2
Nov311, 03:43 PM

P: 349

anyone?




#3
Nov311, 04:25 PM

HW Helper
P: 6,189

Hi Highway!
You have an expression for the projection. Can you substitute that (and only that) in the formula you have for w? To show that 2 vectors are orthogonal, you need to show that their dot product is zero. That is, that [itex]\vec a \cdot \vec w = 0[/itex]. What you need to know, is that there are calculation rules for dot products. For instance [itex]\vec a \cdot (\vec b+\vec c) = \vec a \cdot \vec b + \vec a \cdot \vec c[/itex]. Can you simplify the expression for [itex]\vec a \cdot \vec w = 0[/itex]? 



#4
Nov311, 04:45 PM

P: 349

[Dot Product] Vector Proection 


Register to reply 
Related Discussions  
Vector product VS dot product in matrix  Linear & Abstract Algebra  6  
Vector Algebra  Vector Triple Product Proof  Calculus & Beyond Homework  14  
Vector product  Introductory Physics Homework  2  
Vector product  operator's a vector?  Differential Equations  7  
Vector Product  Linear & Abstract Algebra  4 