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why is dark energy necessary? |
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| Oct21-11, 09:27 PM | #52 |
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why is dark energy necessary?Doesn't feel right trying to debunk something that's concrete and right in front of us, by invoking something so speculative and distant. |
| Oct26-11, 11:40 PM | #53 |
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Ahh, but then we have all those virtual particles too :)
I think they lay in wait, and as they realize that they are in a SpaceTime with planets they pop up to 'push', our typical party pranksters. To get around the question of why they shouldn't push 'evenly' I will now suggest that they 'push' on 'space'. To get around those now arguing that 'space' therefore is a aether, ahh, I will now suggest that they 'push' on 'gravity'.. So there, a perfectly reasonable explanation, covering ahh, a lot. No I'm not serious, but I've been waiting on someone using 'virtual particles' for the longest time :) |
| Oct29-11, 07:45 PM | #54 |
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| Nov5-11, 01:43 PM | #55 |
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| Nov5-11, 10:00 PM | #56 |
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that is very interesting, where does the mass go if photons are massless?
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| Nov5-11, 10:25 PM | #57 |
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oh, OK, they don't have "rest" mass, but they aren't at rest. I wasn't aware they had mass when traveling.
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| Nov6-11, 09:47 AM | #58 |
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| Nov6-11, 04:09 PM | #59 |
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| Nov6-11, 04:46 PM | #60 |
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| Nov6-11, 05:12 PM | #61 |
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Edit: I think that radiation pressure DOES happen to everything. The Sun is pushing objects away from it all the time. However the force of this pressure is extremely small and it also falls off exponentially with range. So while it probably does contribute to a very very slight "expansion", it is many orders of magnitude too small to cause the effect we see on a universal scale. See the table here: http://en.wikipedia.org/wiki/Radiati...lanetary_space Notice that at a distance of 1 AU the pressure is 100 times LESS than it is at 0.1 AU from the Sun. For 4 light years the amount of pressure is 63,990,987,667.36 times LESS than it is at 1 AU. So the nearest star experiences 64 billion times less radiation pressure from the Sun than the Earth does. (Pressure falls off at the square of the distance from the emitting object. 4 Lightyears = 252,964.4 AU. 252,964.4^2 = 63,990,987,667.36) Edit 2: For a star at the other end of our galaxy, 100,000 ly away, assuming the light could even reach it without being absorbed first, which it cant, the pressure would be 39,994,367,292,100,000,000 times less. (That's almost 40 quintillion times less. About 40 billion billion times less) I really hope all my math is correct lol. |
| Nov6-11, 06:52 PM | #62 |
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What I am questioning is if the total quantity of energy released through nuclear fusion throughout the history of the universe is enough to equal the acceleration we observe. Not if we see certain effects on certain systems. As a whole, the proportion between how much energy is necessary to accelerate the universe as we see, and the amount of energy released in stars throughout time.... is that a known ratio?
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| Nov6-11, 06:55 PM | #63 |
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| Nov6-11, 07:32 PM | #64 |
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| Nov6-11, 07:49 PM | #65 |
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Now, don't get me wrong, I DO get (now that you've mentioned it twice ... I'm a little slow sometimes) that you are NOT asking about a mechanism, but do you see my point that your question as asked really does bring in a mechanism, else is somewhat meaningless? |
| Nov6-11, 08:04 PM | #66 |
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It seems to me that the question of meaningless or meaningful, rests on the relationship of the quantities of energy involved.
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| Nov6-11, 08:13 PM | #67 |
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I am just curious, is this an understood proportion?
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| Nov6-11, 08:13 PM | #68 |
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You might as well add up all the fuel costs for all ocean going vessels this year and compare it to all the fuel costs for automobiles for this year. What does that comparison tell you? Nothing meaningful about the realtionship between ships and cars. |
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| acceleration, dark energy, universe |
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