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Uniformly Magnetized Cylinder (B/H Field) |
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| Nov23-11, 08:20 PM | #1 |
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Uniformly Magnetized Cylinder (B/H Field)
1. The problem statement, all variables and given/known data
See figure attached. 2. Relevant equations 3. The attempt at a solution Can someone explain to me why he uses, [tex](z' -z) \quad \text{ and } \quad dz'[/tex] What is the meaning of the ' ? When I did this question, I preformed the integration with the limits from 0 to L with the z in tact using a differential dz. Is that wrong? |
| Nov24-11, 09:15 PM | #2 |
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Still looking for some help!
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| Nov24-11, 11:21 PM | #3 |
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He's using [itex]z[/itex] to be the coordinate of the point where we want to calculate the magnetic field, and using [itex]z'[/itex] to be the coordinate of the current loop. The distance from the current loop to the point is [itex]z - z'[/itex], but he probably skipped a step and used [itex]z' - z[/itex] instead because [itex](z-z')^2 = (z' - z)^2[/itex]. To consider the effects of all the loops from coordinate [itex]0[/itex] to [itex]L[/itex], you have to integrate w.r.t. [itex]z'[/itex] from [itex]0[/itex] to [itex]L[/itex].
If you've integrated w.r.t. [itex]z[/itex] from [itex]0[/itex] to [itex]L[/itex], then you've found the magnetic field at coordinate [itex]0[/itex], but you haven't found the magnetic field at a general coordinate [itex]z[/itex]. |
| Nov25-11, 12:36 PM | #4 |
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Uniformly Magnetized Cylinder (B/H Field)I'd like to see the other perspectives if there are any. |
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