New Reply

Uniformly Magnetized Cylinder (B/H Field)

 
Share Thread Thread Tools
Nov23-11, 08:20 PM   #1
 

Uniformly Magnetized Cylinder (B/H Field)


1. The problem statement, all variables and given/known data

See figure attached.

2. Relevant equations



3. The attempt at a solution

Can someone explain to me why he uses,

[tex](z' -z) \quad \text{ and } \quad dz'[/tex]

What is the meaning of the ' ?

When I did this question, I preformed the integration with the limits from 0 to L with the z in tact using a differential dz.

Is that wrong?
Attached Thumbnails
2008FQ2.JPG  
PhysOrg.com
PhysOrg
science news on PhysOrg.com

>> Ants and carnivorous plants conspire for mutualistic feeding
>> Forecast for Titan: Wild weather could be ahead
>> Researchers stitch defects into the world's thinnest semiconductor
Nov24-11, 09:15 PM   #2
 
Still looking for some help!
Nov24-11, 11:21 PM   #3
 
He's using [itex]z[/itex] to be the coordinate of the point where we want to calculate the magnetic field, and using [itex]z'[/itex] to be the coordinate of the current loop. The distance from the current loop to the point is [itex]z - z'[/itex], but he probably skipped a step and used [itex]z' - z[/itex] instead because [itex](z-z')^2 = (z' - z)^2[/itex]. To consider the effects of all the loops from coordinate [itex]0[/itex] to [itex]L[/itex], you have to integrate w.r.t. [itex]z'[/itex] from [itex]0[/itex] to [itex]L[/itex].

If you've integrated w.r.t. [itex]z[/itex] from [itex]0[/itex] to [itex]L[/itex], then you've found the magnetic field at coordinate [itex]0[/itex], but you haven't found the magnetic field at a general coordinate [itex]z[/itex].
Nov25-11, 12:36 PM   #4
 

Uniformly Magnetized Cylinder (B/H Field)


Quote by omoplata View Post
He's using [itex]z[/itex] to be the coordinate of the point where we want to calculate the magnetic field, and using [itex]z'[/itex] to be the coordinate of the current loop. The distance from the current loop to the point is [itex]z - z'[/itex], but he probably skipped a step and used [itex]z' - z[/itex] instead because [itex](z-z')^2 = (z' - z)^2[/itex]. To consider the effects of all the loops from coordinate [itex]0[/itex] to [itex]L[/itex], you have to integrate w.r.t. [itex]z'[/itex] from [itex]0[/itex] to [itex]L[/itex].

If you've integrated w.r.t. [itex]z[/itex] from [itex]0[/itex] to [itex]L[/itex], then you've found the magnetic field at coordinate [itex]0[/itex], but you haven't found the magnetic field at a general coordinate [itex]z[/itex].
Is there any other way you can reason this problem out without using the z'?

I'd like to see the other perspectives if there are any.
New Reply
Thread Tools


Similar Threads for: Uniformly Magnetized Cylinder (B/H Field)
Thread Forum Replies
Uniformly Charged Cylinder - Potential at distance d? Introductory Physics Homework 0
Electric Field due to a charged hallow cylinder/solid cylinder on a point Introductory Physics Homework 7
E-Field over Uniformly Charged Disc Introductory Physics Homework 9
Uniformly polarized cylinder Advanced Physics Homework 1
uniformly charged cylinder Introductory Physics Homework 4