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Normalization of a wavefunction |
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| Jan2-12, 07:46 AM | #1 |
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Normalization of a wavefunction
1. The problem statement, all variables and given/known data
This is a multi-choice question. A particle of unit mass moving in an infinite square well, V = 0 for lxl ≤ a V = ∞ for lxl > a is described by the wavefunction, u(x) = A sin (3∏x/a) If the wavefunction is normalised, What is A? a) 1/2a b) 1/√2a c) 1/√a 2. Relevant equations I know that the integral of the wavefn squared is equal to 1 because it has to exist somewhere but when I tried integrating it, it either all went to 1 or ∞. I know how to do this question, I just can't. An easy to follow mathematical proof would be most helpful. 3. The attempt at a solution I am integrating between ∞ and -∞ is that correct? so far i've got that ∫ A2 sin2 (3∏x/a) dx = 1 using the identity: cos (2x) = 1 - 2 sin2(x) = A2/2 ∫ 1 - cos (6∏x/a) dx = 1 And now i'm stuck... |
| Jan2-12, 08:01 AM | #2 |
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| Jan2-12, 08:14 AM | #3 |
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Ah ok, I thought the wave function wouldn't exist outside of the square well so the wave function would be zero..?
I got the sin (3∏x/a) wavefunction given to me in the question so I just took it as true. |
| Jan2-12, 08:52 AM | #4 |
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Normalization of a wavefunction
yes, you're right. The wave function outside the square well is zero. and inside the well, it is sin (3∏x/a). Also, you were right that the integral is from -∞ to ∞. But what is the integrand for lxl > a ?
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| Jan2-12, 09:08 AM | #5 |
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I don't know. This is just a guess would it be,
between 0 and a ∫ A sin (3∏x/a) dx This is where I get confused, because I thought to do this question all I have to do is square the wavefunction and integrate between -∞ and ∞. Is there another step before hand? |
| Jan2-12, 09:22 AM | #6 |
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the wave function is A sin (3∏x/a) for lxl ≤ a and it is zero for lxl > a
So you do need to 'square the wavefunction and integrate between -∞ and ∞', but the wave function will be zero for lxl > a In other words, you need to identify the different 'sections' and integrate each section, to get the integration over all space. |
| Jan2-12, 09:46 AM | #7 |
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Sorry if I'm being slow and thanks for your help.
but would one of the sections be an integral between a and -a ? Do I do that and then integrate between -∞ and ∞? |
| Jan2-12, 10:10 AM | #8 |
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no worries. Yeah, one section would be from -a to a. The total integral is from -∞ to ∞, so what would the other sections be?
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| normalisation, quantum, wave function |
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