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Distributed Loads. Simple question 
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#1
Jan912, 05:44 AM

P: 25

Hi there,
Parallel distributed loads are throwing me off a little at the moment. Is the resultant worked out the same way as for those with distributed loads perpendicular to a beam?? Picture included. Thanks in advance 


#2
Jan912, 09:57 AM

P: 25

lotsa views yet no help..
please post a reply?? 


#3
Jan912, 10:31 AM

Sci Advisor
PF Gold
P: 2,248

An axial distributed load such as you've drawn would have a cumulative effect, so the force at the right end of the beam would be the sum of all forces to its left. In effect, you've drawn a force which increases with position from left to right.



#4
Jan912, 10:35 AM

P: 25

Distributed Loads. Simple question
Thx :)



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