Distributed Loads. Simple question

tigertan

Hi there,


Parallel distributed loads are throwing me off a little at the moment. Is the resultant worked out the same way as for those with distributed loads perpendicular to a beam??


Picture included.

Thanks in advance

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tigertan

lotsa views yet no help..

please post a reply??

Mech_Engineer

An axial distributed load such as you've drawn would have a cumulative effect, so the force at the right end of the beam would be the sum of all forces to its left. In effect, you've drawn a force which increases with position from left to right.

tigertan

Thx :)