Distributed Loads. Simple question


by tigertan
Tags: distributed, loads, simple
tigertan
tigertan is offline
#1
Jan9-12, 05:44 AM
P: 25
Hi there,


Parallel distributed loads are throwing me off a little at the moment. Is the resultant worked out the same way as for those with distributed loads perpendicular to a beam??


Picture included.

Thanks in advance
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tigertan
tigertan is offline
#2
Jan9-12, 09:57 AM
P: 25
lotsa views yet no help..

please post a reply??
Mech_Engineer
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#3
Jan9-12, 10:31 AM
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An axial distributed load such as you've drawn would have a cumulative effect, so the force at the right end of the beam would be the sum of all forces to its left. In effect, you've drawn a force which increases with position from left to right.

tigertan
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#4
Jan9-12, 10:35 AM
P: 25

Distributed Loads. Simple question


Thx :)


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