# rate of effusion dependance on pressure

by jd12345
Tags: dependance, effusion, pressure, rate
 P: 260 In my class rate of effusion was told to be directly proportional to the mean speed of gas molecules which is intuitive and i understand. RMS speed of molecules is √3RT/M So rate of effusion is inversely proportional to sqaure root of molar mass But i dont understand how rate of effusion is directly proportional to pressure RT = PV So RMS speed = √PV/M so rate of effusion should be proportional to square root of pressure right? But apparently its not, plz explain me why Thank you!
P: 403
 Quote by jd12345 In my class rate of effusion was told to be directly proportional to the mean speed of gas molecules which is intuitive and i understand. RMS speed of molecules is √3RT/M So rate of effusion is inversely proportional to sqaure root of molar mass But i dont understand how rate of effusion is directly proportional to pressure RT = PV So RMS speed = √PV/M so rate of effusion should be proportional to square root of pressure right? But apparently its not, plz explain me why Thank you!
It makes more sense if you replace PV=RT with the statistical mechanical equation of state,
P = nkT. Then the number density (number of molecules per unit volume) is directly proportional to the pressure. The more molecules per unit volume, the greater the effusion through an opening.

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