# ODE Approaching the expicit solution

by freestar
Tags: approaching, expicit, solution
 P: 1 Hi there, This ode has me really stumped. Since it is non linear, I don't know which method to use for this: $$xy' + 2y = \frac{sec^2(y)}{x}$$ Thank you :)
 P: 52 There are two hints that may be useful (or not). $\frac{d(tan(y))}{dy}=?$ $\frac{d(x^2 y)}{dx}=?$
 Quote by coelho There are two hints that may be useful (or not). $\frac{d(tan(y))}{dy}=?$ $\frac{d(x^2 y)}{dx}=?$