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Where does the energy vanish to when light is red shifted 
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#1
Feb1712, 07:06 PM

P: 10

When light is red shifted due to the expansion of the universe, it loses energy (E=hf). Doesn't the "conservation of energy rule" apply in this case? Where does all that energy vanish to?



#2
Feb1712, 07:44 PM

Mentor
P: 11,872

Conservation of energy does not apply at the cosmological scale, contrary to what you would expect. Guacamolewar, your description applies for standard redshift due to the doppler effect, but the problem is that light is redshifted to ALL frames of reference in the universe and is never blueshifted. The energy is disappearing. To my knowledge energy is not a well described feature in General Relativity.



#3
Feb1712, 08:36 PM

P: 226




#4
Feb1712, 08:50 PM

Astronomy
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PF Gold
P: 23,227

Where does the energy vanish to when light is red shifted
By making special assumptions you can partially recover in certain cases but as a general rule "energy is not conserved in expanding geometry" People try to cushion the shock by talking about "energy of the gravitational field" but this is not always globally defined. The simplest is just to face it. The CMB ancient light is redshifted by z=1100. Therefore it has lost some 99.9% of its energy and nobody can say where "it went". There's probably something about this in the FAQ. There also is a bit in John Baez FAQ. The flat nonexpanding geometry of Special Rel is only APPROXIMATELY right. Be grateful for that much. It is not perfectly realistic. General Rel is a little bit closer to nature, and some of the things you expect are only approximately correct. 


#5
Feb1712, 09:04 PM

P: 226

Is the restoration of conservation of energy on the universal scale desired at all in current physics? 


#6
Feb1712, 09:40 PM

Astronomy
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PF Gold
P: 23,227

It doesn't add up. No professionalgrade math connects one to the other AFAIK. It is just an appealing idea that has not amounted to anything (AFAIK!) You might want to read this article (quite a lot is nontechnical): Google "bianchi prejudices against constant". the cosmologists Lambda seems very likely just a constant (a curvature not an energy) and does not necessarily have any simple relation to the QFT "vacuum energy". It is only the QFT people who insist on thinking of their "vacuum energy" as related to Lambda. Lambda can simply be a natural constant like newton G, not really anything that needs to be called "dark energy". I suggest you try the idea out, if not already familiar to you. When you google "bianchi prejudices against constant" you get http://arxiv.org/abs/1002.3966. The article's title is "Why All These Prejudices Against a Constant?" Interesting reading. 


#7
Feb1812, 12:30 AM

P: 226

Oh, how far short were you? Or was the lost photon energy actually too much to be accounting for the "dark energy"? 


#8
Feb1812, 01:27 AM

Sci Advisor
PF Gold
P: 9,445

Energy is not well defined in GR, hence the 'missing' energy enigma. It is obviously difficult to explain 'conservation' of anything that is undefined.



#9
Feb1812, 11:06 AM

PF Gold
P: 184

Is energy also nonconserved in GR due to local curvature? For example, If a system consists of a hollow spherical reflector with lots of photons bouncing around inside, and it collapses to a BH, does the equivalent gravitational mass of the system change as measured by a distant observer?



#10
Feb1812, 02:03 PM

P: 476




#11
Feb1812, 02:48 PM

Astronomy
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PF Gold
P: 23,227

I also have the impression that one ought to be able to treat this example in a space that is asymptotically flat (ordinary nonexpanding space out at the limit far away from the collapse). My intuition is not reliable but my hunch is that one should expect ordinary energy conservation in this case. What is your hunch? If we go with my naive suspicion that conservation holds with this being asymptotically flat (out where your observer is) then it seems to me that it leads to a paradox. Is there some relevant literature? 


#12
Feb1812, 03:40 PM

PF Gold
P: 184

If a sphericallysymmetric collapse of this system changed its equivalent mass, the collapse would sent out gravity waves. I am under the impression that a closed system which undergoes sphericallysymmetric oscillations cannot send out gravity waves. This includes any kinetic energy that a massive shell acquires as it collapses. I would guess then that the equivalent mass of the reflectorphoton system is unchanged by the collapse.
In expansion, any motion of massive particles with respect to the comoving frame is reduced over time, and this effect (in addition to photon wavelength increase) contributes to the global nonconservation of energy. If spherical oscillations do not send out gravity waves and if this statement is true even if the massive particles start with some relative motions, then the reflectorphoton system will conserve energy. 


#13
Feb2612, 02:23 AM

P: 1

Can this question be usefully reversed? Could some of the observed red shift be the result of photons shedding energy in some way that is difficult measure on human timescales? Could this hypothesis help to explain the observed increase in the rate of expansion of spacetime?



#14
Feb2612, 06:32 AM

Sci Advisor
PF Gold
P: 9,445

Obviously spacetime is not conserved in an expanding universe. I've always been attracted to the idea that expansion dilutes energy. An ink dot on a ballon starts out as ... a dot, but, grows as the balloon is inflated. All the ink is still there, just spread out.



#15
Jan1413, 01:04 PM

P: 199

I too have trouble with the idea of nonconservation of energy in general relativity. As the universe expands, of course the energy density will decease, but the integral of the energy density (i.e. the total energy) of the universe should be constant. At least I would imagine it so. So do cosmologists say that in an open universe as we approach heat death, that both the energy density and the energy approach zero? 


#16
Jan1513, 01:16 PM

P: 76




#17
Jan1513, 08:36 PM

P: 10

Aren't the photons stretched in length so that the redshifted photons are longer to make up for their decreased frequency. I'm sure this is a dumb question



#18
Jan1513, 10:05 PM

Sci Advisor
PF Gold
P: 9,445

Redshift is a frame dependent measurement. If you were approaching a distant galaxy at the same speed as it is receeding, you would see no redshift. The problem arises when you try to compare photon energy in different reference frames. It is sort of like a baseball player chasing a line drive. If you run toward the ball it hits your glove with more force than it does if you catch it running toward the fence. A stationary observer, however, would perceive no difference in the kinetic energy of the baseball.



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