|Feb21-12, 10:40 PM||#1|
Generating full sequence with complex numbers.
I need some help with the following: I understand that by using xn = axn-1+b we can generate a full sequence of numbers. For example, if x1=ax0+b, then x2 = ax1+b = a2x0+ab+b, and so on and so forth to xn. I need help applying this same concept to complex numbers (a+bi). Is it even possible? I think it is, but I can't figure it out. Can some one lend a hand?
|Feb22-12, 04:48 AM||#2|
this is a recurrence relation
its solutions should be of the same form, whether the constants are real or complex
were you having a problem with any particular relation?
|Feb22-12, 09:20 AM||#3|
Well, my professor began to explain the relation among real numbers, and he explained for x0, x1, x2, etc. He mentioned that the same could be done with complex numbers, but never went into detail, maybe he will explain later. It piqued my curiosity, but I can't figure out how to generate a full sequence using the same method above only with something of the form a+bi.
|Similar Threads for: Generating full sequence with complex numbers.|
|Generating function for r as sum of odd numbers, each of which occurs at most 3 times||General Math||0|
|Generating functions and Recurrence relations using the Fibonacci sequence||Calculus & Beyond Homework||0|
|Generating Kimberling Sequence||General Math||0|
|Lucas Numbers and Generating Functions||Calculus & Beyond Homework||4|
|generating prime numbers||Linear & Abstract Algebra||12|