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Linked list sorting method in java

by schapman22
Tags: java, linked, list, method, sorting
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schapman22
#1
Feb21-12, 02:27 PM
P: 74
1. The problem statement, all variables and given/known data
I need to write a sorting method for my IntNode class. this is supposed to use the selection sort algorithm.


2. Relevant equations
selection sort algorithm given by problem

while(the first list still has some nodes
{
1. find the node with the largest element of all the nodes in the first list.
2. Remove this node from the first list.
3. Add this node at the head of the second list.

3. The attempt at a solution

public class IntNode
{
   // Invariant of the IntNode class:
   //   1. The node's integer data is in the instance variable data.
   //   2. For the final node of a list, the link part is null.
   //      Otherwise, the link part is a reference to the
   //      next node of the list.
   private int data;
   private IntNode link;   


   /**
   * Initialize a node with a specified initial data and link to the next
   * node. Note that the initialLink may be the null reference, 
   * which indicates that the new node has nothing after it.
   * @param initialData
   *   the initial data of this new node
   * @param initialLink
   *   a reference to the node after this new node--this reference may be null
   *   to indicate that there is no node after this new node.
   * @postcondition
   *   This node contains the specified data and link to the next node.
   **/   
   public IntNode(int initialData, IntNode initialLink)
   {
      data = initialData;
      link = initialLink;
   }


   /**
   * Modification method to add a new node after this node.   
   * @param item
   *   the data to place in the new node
   * @postcondition
   *   A new node has been created and placed after this node.
   *   The data for the new node is item. Any other nodes
   *   that used to be after this node are now after the new node.
   * @exception OutOfMemoryError
   *   Indicates that there is insufficient memory for a new 
   *   IntNode. 
   **/
   public void addNodeAfter(int item)   
   {
      link = new IntNode(item, link);
   }          
   
   
   /**
   * Accessor method to get the data from this node.   
   * @param - none
   * @return
   *   the data from this node
   **/
   public int getData( )   
   {
      return data;
   }
   
   
   /**
   * Accessor method to get a reference to the next node after this node. 
   * @param - none
   * @return
   *   a reference to the node after this node (or the null reference if there
   *   is nothing after this node)
   **/
   public IntNode getLink( )
   {
      return link;                                               
   } 
    
    
   /**
   * Copy a list.
   * @param source
   *   the head of a linked list that will be copied (which may be
   *   an empty list in where source is null)
   * @return
   *   The method has made a copy of the linked list starting at 
   *   source. The return value is the head reference for the
   *   copy. 
   * @exception OutOfMemoryError
   *   Indicates that there is insufficient memory for the new list.   
   **/ 
   public static IntNode listCopy(IntNode source)
   {
      IntNode copyHead;
      IntNode copyTail;
      
      // Handle the special case of the empty list.
      if (source == null)
         return null;
         
      // Make the first node for the newly created list.
      copyHead = new IntNode(source.data, null);
      copyTail = copyHead;
      
      // Make the rest of the nodes for the newly created list.
      while (source.link != null)
      {
         source = source.link;
         copyTail.addNodeAfter(source.data);
         copyTail = copyTail.link;
      }
 
      // Return the head reference for the new list.
      return copyHead;
   }
   
   
   /**
   * Copy a list, returning both a head and tail reference for the copy.
   * @param source
   *   the head of a linked list that will be copied (which may be
   *   an empty list in where source is null)
   * @return
   *   The method has made a copy of the linked list starting at 
   *   source.  The return value is an
   *   array where the [0] element is a head reference for the copy and the [1]
   *   element is a tail reference for the copy.
   * @exception OutOfMemoryError
   *   Indicates that there is insufficient memory for the new list.   
   **/
   public static IntNode[ ] listCopyWithTail(IntNode source)
   {
      IntNode copyHead;
      IntNode copyTail;
      IntNode[ ] answer = new IntNode[2];
     
      // Handle the special case of the empty list.   
      if (source == null)
         return answer; // The answer has two null references .
      
      // Make the first node for the newly created list.
      copyHead = new IntNode(source.data, null);
      copyTail = copyHead;
      
      // Make the rest of the nodes for the newly created list.
      while (source.link != null)
      {
         source = source.link;
         copyTail.addNodeAfter(source.data);
         copyTail = copyTail.link;
      }
      
      // Return the head and tail references.
      answer[0] = copyHead;
      answer[1] = copyTail;
      return answer;
   }
   
   
   /**
   * Compute the number of nodes in a linked list.
   * @param head
   *   the head reference for a linked list (which may be an empty list
   *   with a null head)
   * @return
   *   the number of nodes in the list with the given head 
   * @note
   *   A wrong answer occurs for lists longer than Int.MAX_VALUE.     
   **/   
   public static int listLength(IntNode head)
   {
      IntNode cursor;
      int answer;
      
      answer = 0;
      for (cursor = head; cursor != null; cursor = cursor.link)
         answer++;
        
      return answer;
   }
   

   /**
   * Copy part of a list, providing a head and tail reference for the new copy. 
   * @param start/end
   *   references to two nodes of a linked list
   * @param copyHead/copyTail
   *   the method sets these to refer to the head and tail node of the new
   *   list that is created
   * @precondition
   *   start and end are non-null references to nodes
   *   on the same linked list,
   *   with the start node at or before the end node. 
   * @return
   *   The method has made a copy of the part of a linked list, from the
   *   specified start node to the specified end node. The return value is an
   *   array where the [0] component is a head reference for the copy and the
   *   [1] component is a tail reference for the copy.
   * @exception IllegalArgumentException
   *   Indicates that start and end are not references
   *   to nodes on the same list.
   * @exception NullPointerException
   *   Indicates that start is null.
   * @exception OutOfMemoryError
   *   Indicates that there is insufficient memory for the new list.    
   **/   
   public static IntNode[ ] listPart(IntNode start, IntNode end)
   {
      IntNode copyHead;
      IntNode copyTail;
      IntNode cursor;
      IntNode[ ] answer = new IntNode[2];
      
      // Make the first node for the newly created list. Notice that this will
      // cause a NullPointerException if start is null.
      copyHead = new IntNode(start.data, null);
      copyTail = copyHead;
      cursor = start;
      
      // Make the rest of the nodes for the newly created list.
      while (cursor != end)
      {
         cursor = cursor.link;
         if (cursor == null)
            throw new IllegalArgumentException
            ("end node was not found on the list");
         copyTail.addNodeAfter(cursor.data);
         copyTail = copyTail.link;
      }
      
      // Return the head and tail references
      answer[0] = copyHead;
      answer[1] = copyTail;
      return answer;
   }        
   
   
   /**
   * Find a node at a specified position in a linked list.
   * @param head
   *   the head reference for a linked list (which may be an empty list in
   *   which case the head is null)
   * @param position
   *   a node number
   * @precondition
   *   position > 0.
   * @return
   *   The return value is a reference to the node at the specified position in
   *   the list. (The head node is position 1, the next node is position 2, and
   *   so on.) If there is no such position (because the list is too short),
   *   then the null reference is returned.
   * @exception IllegalArgumentException
   *   Indicates that position is not positive.    
   **/   
   public static IntNode listPosition(IntNode head, int position)
   {
      IntNode cursor;
      int i;
      
      if (position <= 0)
           throw new IllegalArgumentException("position is not positive");
      
      cursor = head;
      for (i = 1; (i < position) && (cursor != null); i++)
         cursor = cursor.link;

      return cursor;
   }


   /**
   * Search for a particular piece of data in a linked list.
   * @param head
   *   the head reference for a linked list (which may be an empty list in
   *   which case the head is null)
   * @param target
   *   a piece of data to search for
   * @return
   *   The return value is a reference to the first node that contains the
   *   specified target. If there is no such node, the null reference is 
   *   returned.     
   **/   
   public static IntNode listSearch(IntNode head, int target)
   {
      IntNode cursor;
      
      for (cursor = head; cursor != null; cursor = cursor.link)
         if (target == cursor.data)
            return cursor;
        
      return null;
   }

   
   /**
   * Modification method to remove the node after this node.   
   * @param - none
   * @precondition
   *   This node must not be the tail node of the list.
   * @postcondition
   *   The node after this node has been removed from the linked list.
   *   If there were further nodes after that one, they are still
   *   present on the list.
   * @exception NullPointerException
   *   Indicates that this was the tail node of the list, so there is nothing
   *   after it to remove.
   **/
   public void removeNodeAfter( )   
   {
      link = link.link;
   }          
   
   
   /**
   * Modification method to set the data in this node.   
   * @param newData
   *   the new data to place in this node
   * @postcondition
   *   The data of this node has been set to newData.
   **/
   public void setData(int newData)   
   {
      data = newData;
   }                                                               
   
   
   /**
   * Modification method to set the link to the next node after this node.
   * @param newLink
   *   a reference to the node that should appear after this node in the linked
   *   list (or the null reference if there is no node after this node)
   * @postcondition
   *   The link to the node after this node has been set to newLink.
   *   Any other node (that used to be in this link) is no longer connected to
   *   this node.
   **/
   public void setLink(IntNode newLink)
   {                    
      link = newLink;
   }
   
   public void printRange(IntNode head, int x, int y)
   {
       for (IntNode cursor = head; cursor!=null; cursor = cursor.link)
       {
           if(cursor.data>=x && cursor.data<=y)
               System.out.println(cursor.data);
       }
   }
   
   public static IntNode removeDuplicates(IntNode h)
   {
       IntNode copyHead = new IntNode (h.data, null);
       IntNode cursor2 = copyHead;

       for(IntNode cursor=h.link;cursor!=null; cursor=cursor.link)
       {
           if(!(IntNode.listSearch2(copyHead,cursor.data)))
           {
              cursor2.addNodeAfter(cursor.data);
              cursor2 = cursor2.link;
           }
        }
       return copyHead;
   }

   public static boolean listSearch2(IntNode head, int target)
   {
      IntNode cursor;

      for (cursor = head; cursor != null; cursor = cursor.link)
         if (target == cursor.data)
            return true;

      return false;
   }
   
    public static IntNode reverseList(IntNode head) 
    {

        int i;
        int length = IntNode.listLength(head);
        IntNode copyHead, cursor;
        IntNode copyTail = IntNode.listPosition(head, length);
        copyHead = new IntNode(copyTail.data, null);
        cursor = copyHead;
        for (i = length - 1; i >= 1; i--) 
        {
            copyTail = IntNode.listPosition(head, i);
            cursor.addNodeAfter(copyTail.data);
            cursor = cursor.getLink();
        }
        return copyHead;
    }
   
   public static IntNode listSort(IntNode head)
   {
       IntNode copyHead, previous;
       int length = IntNode.listLength(head), largest = -1;
       
       while(head!=null)
       {
           for(IntNode cursor=head;cursor!=null;cursor=cursor.link)
           {
               if(cursor.data > largest)
                   largest = cursor.data;
           }        
       }
   }
       
}
Sorry I know it is a long class but I want you to see what methods I have to work with. The listSort() method is the last one and as you can see I have only completed step 1. Thank you in advance.
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jedishrfu
#2
Feb21-12, 03:05 PM
P: 2,809
first you're assuming the nodes contain positive values as you've initialized the largest to -1 instead I think you should use largest = Integer.MIN_VALUE.

In pseudo code:
1) use the head node find the node containing the highest value
2) add that highest node to your new list
3) delete that highest node from the list of original nodes
4) repeat steps 1 thru 4 until there's no more nodes in the orignal list
schapman22
#3
Feb21-12, 03:12 PM
P: 74
thanks that helps heres what I have so far for the method but what happens is it creates a new list the same length but with the largest integer for all nodes.

public static IntNode listSort(IntNode head)
   {
       IntNode copyHead=null, previous;
       int length = IntNode.listLength(head), largest = Integer.MIN_VALUE;
       
       while(head!=null)
       {
           for(IntNode cursor=head;cursor!=null;cursor=cursor.link)
           {
               if(cursor.data > largest)
                   largest = cursor.data;
           }
           copyHead = new IntNode(largest, copyHead);
           head = head.link;
       }
       return copyHead;
   }

jedishrfu
#4
Feb21-12, 04:21 PM
P: 2,809
Linked list sorting method in java

on each loop thru looking for the largest don't you have to reset the largest back to Integer.MIN_VALUE?

it looks like your solution only makes one pass thru the list to find the largest. also your original head value is getting changed with head=head.link assignment so on your next pass you won't know where to begin.
schapman22
#5
Feb21-12, 05:14 PM
P: 74
I tried resetting it and it wont work, and I need head=head.link or else it will be an infinite loop. Do you have any suggestions how to accomplish these things?
schapman22
#6
Feb21-12, 05:24 PM
P: 74
public static IntNode listSort(IntNode head)
   {
       IntNode cursor;
       int largest = Integer.MIN_VALUE;
       
       IntNode copyHead=null;
       while(head!=null)
       {
           for(cursor=head.link;cursor!=null;cursor=cursor.link)
           {
               if(cursor.data > largest)
               {
                   largest = cursor.data;
               }
           }
           copyHead=new IntNode(largest, copyHead);
           largest = Integer.MIN_VALUE;
           head=head.link;
       }
       return copyHead;
   }
tried this but still doesnt work
schapman22
#7
Feb21-12, 06:26 PM
P: 74
nobody has any suggestions?
Mark44
#8
Feb21-12, 06:54 PM
Mentor
P: 21,215
Mod note: Thread moved to the Homework & Coursework subforum, which is where it should be.
schapman22
#9
Feb21-12, 07:58 PM
P: 74
public static IntNode listSort(IntNode head)
   {
       IntNode cursor;
       int largest;
       IntNode copyHead=null;
       IntNode target=null;
       while(head!=null)
       {
           largest = Integer.MIN_VALUE;
           for(cursor=head.link;cursor!=null;cursor=cursor.link)
           {
               if(cursor.data > largest)
               {
                   target=cursor;
                   largest=cursor.data;
               }
           }
           copyHead = new IntNode(target.data, copyHead);
           target.setData(head.data);
           head=head.link;
       }
       return copyHead;
   }
this is the closest I have gotten so far. It works about half of the time, and the other half it is off by 1. I tested many different sets of numbers, it seems random when it does or does not work.
rcgldr
#10
Feb21-12, 11:02 PM
HW Helper
P: 7,046
Is this supposed to be a single linked list (a next link, but no previous link?) If so, removing a node from the list will require usage of some additional variables.
Joffan
#11
Feb22-12, 01:20 AM
P: 361
Suggestions
1. Try moving the nodes without copying the data (ie. don't make new nodes).
2. You need to keep sight of the node before the select move target node, so that you can re-make the links in the original list after you move the target node.
rcgldr
#12
Feb22-12, 11:24 AM
HW Helper
P: 7,046
Quote Quote by Joffan View Post
2. You need to keep sight of the node before the select move target node.
I think Joffan means you need to keep track of the node prior to "target", in a separate variable, which I mentioned before. One complication occurs if "target" is the first node in a list (because then you'll be updating head.link when you remove "target" from the list).

I don't see a separate declaration for the "head" or a "list" class (which would include a head link), or are you using a "node" class for the "head" link?


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